rag1999 rag1999
  • 02-05-2018
  • Mathematics
contestada

h^-2g for h=3 and g=27

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Аноним Аноним
  • 02-05-2018
Plug h = 3 and g = 27 into the expression:

[tex]h^{-2}g= \dfrac{g}{h^2} = \dfrac{27}{3^2} = \dfrac{27}{9} = 3[/tex]
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