Answer with Step-by-step explanation:
As we can see from the graph:
A=(0,0) and A'=(2,1)
Distance between (x1,y1) and (x2,y2) is given by:
[tex]\sqrt{{(x1-x2)}^2+{(y1-y2)}^2}[/tex]
Here (x1,y1)=(0,0) and (x2,y2)=(2,1)
Hence, distance between A and A' is:
[tex]\sqrt{{(0-2)}^2+{(0-1)}^2}[/tex]
= [tex]\sqrt{4+1}[/tex]
= [tex]\sqrt{5}[/tex]
Hence, distance AA'=√5
