If u(x)=-2x^2+3 and v(x)=1/x,what is the range of (uov)(x) ?

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02-09-2017
Mathematics

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If u(x)=-2x^2+3 and v(x)=1/x,what is the range of (uov)(x) ?

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mreijepatmat mreijepatmat · Answer 1 · 2017-09-02T19:24:21+02:00

mreijepatmat mreijepatmat

02-09-2017

u(x)=-2x²+3
v(x)=1/x →→ range of (uоv)(x, BUT range (uov)(x = u(v(x)), then :

u(v(x)) = -2(1/x²) + 3 →→u(v(x)) = -2/x² + 3

The range of -2/x² + 3 = {x∈R/x≠0}

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