The perimeter of rectangle will be 60 cm.
Given,
The smaller side of rectangle is 10 cm.
Let the bigger side of rectangle be [tex]x[/tex] cm.
Since all angles measures 90 degrees in a rectangle so the bisector of one of the angle of rectangle bisects it into two equal angles of 45 degrees each.
As given in question,
The bisector of one of the angles of a rectangle also bisects a side of the rectangle( here bigger side ).
So if we take the triangle with the line joining the angle bisector to the opposite side then the base will be shorter side and the perpendicular will be half of bigger side.
Now consider the right triangle, by trigonometric ratios, we have
[tex]Tan\Theta=\dfrac{Perpendicular}{Base} \\[/tex]
[tex]Tan 45^{\circ}=\dfrac{\frac{x}{2} }{10}[/tex]
[tex]\dfrac{x}{2} =10\ (Tan45^{\circ}=1)[/tex]
[tex]x=20[/tex]
So bigger side will be 20 cm.
We know that the perimeter of rectangle is,
[tex]P=2(L+B)[/tex]
[tex]P=2(10+20)\\P=60 \ cm[/tex]
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