Respuesta :

bunnuika

Answer:

e^-4t e^-5t

Explanation:

solving s²+9s+20 quadratically we have (s+4)(s+5)

x(s) can be written as x(s) =(1/s+4)(1/s+5)

if we take the laplace inversve

L-¹ (s)=L-1(1/s+4) L-1(1/s+5)

we have e^-4t e^-5t