Answer:
p=7/2
Step-by-step explanation:
Rember that a p series can be represented by
[tex] \frac{1}{k {}^{p} } [/tex]
Here, notice that
[tex] \frac{1}{8 \sqrt{2} } = \frac{1}{2 {}^{3} \sqrt{2} } = \frac{1}{2 {}^{3} \times 2 {}^{ \frac{1}{2} } } = \frac{1}{2 {}^{ \frac{7}{2} } } [/tex]
This is true for all parts of the series because
[tex]27 \sqrt{3} = 3 {}^{ \frac{7}{2} } [/tex]
So p=7/2
