Answer:
Step-by-step explanation:
I will ASSUME you mean y = 3x² at x = 2
The derivative of an equation is the slope the curve at any given point
y' = 6x
so our line slope at x = 2 is 6(2) = 12
at x = 2, y = 3(2²) = 12
so (2, 12) is a point on the line (the point of tangency)
plugging into our slope equation
y = 12x + b
12 = 12(2) + b
b = -12
So the equation of the line tangent to y = 3x² at x = 2 is
y = 12x - 12
