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  • 04-08-2021
  • Mathematics
contestada

*Write a linear equation that goes through the points (-2,6) and (1,1).

Respuesta :

Аноним Аноним
  • 04-08-2021

Answer:

Equation of the line is 3y = -5x + 8

Step-by-step explanation:

Slope:

[tex]{ \bf{m = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }}[/tex]

substitute:

[tex]{ \sf{m = \frac{1 - 6}{1 - ( - 2)} }} \\ { \sf{m = - \frac{5}{3} }}[/tex]

General equation of a line:

[tex]{ \boxed{ \pmb{y = mx + b}}}[/tex]

b is the y-intercept.

Consinder point (1, 1):

[tex]{ \sf{1 = ( - \frac{5}{3} \times 1) + b}} \\ { \sf{b = \frac{8}{3} }}[/tex]

Substitute:

[tex]{ \sf{y = - \frac{5}{3} x + \frac{8}{3} }} \\ \\ { \sf{3y = - 5x + 8}}[/tex]

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