Answer:
A point on the circumference of the tire will travel 7.68 ft.
Step-by-step explanation:
Given;
radius of the car tire, r = 1.6 ft
angular distance or rotation = 275⁰
A complete rotation of the tire = 360⁰
the distance a point on the circumference will travel = 2πr
If 360⁰ = 2πr
then 275⁰ = ?
[tex]= \frac{275 \ \times \ 2\pi r}{360} = \frac{275 \ \times \ 2\pi \times 1.6ft}{360} = 7.68 \ ft[/tex]
Therefore, a point on the circumference of the tire will travel 7.68 ft.
