Answer:
(3,-1)
Step-by-step explanation:
[tex]f(x) = x {}^{2} - 6x + 8 \\ y = {x}^{2} - 6x + 8 \\ equation \: is \: in \: the \: form \: of \: ax {}^{2} + bx + c \\ a = 1 \\ b = - 6 \\ c = 8 \\ solve \: for \: x \\ x = \frac{ - b}{2a} = \frac{ - (- 6)}{2 \times 1} = \frac{6}{2 } = 3 \\ substitute \: x = 3 \: in \: the \: original \: equation \\ solve \:for \:y \\ y = 3 ^{2} + (- 6 \times 3) + 8 \\ y = - 1 \\ [/tex]
