Step-by-step explanation:
Given that,
Directrix, d= -5, and eccentricity, e = 2.
The polar equation of the conic is given by :
[tex]r=\dfrac{ed}{1-e\cos\theta}[/tex]
Put all the values,
[tex]r=\dfrac{-5\times 2}{1-2\cos\theta}\\\\=\dfrac{-10}{1-2\cos\theta}[/tex]
As e>1, it is a hyperbola. Hence, this is the required solution.
