Answer:
A. [tex]\bold {x=\dfrac{-3+\sqrt{21}}{2}}[/tex] and D. [tex]\bold {x=\dfrac{-3-\sqrt{21}}{2}}[/tex]
Step-by-step explanation:
[tex]x^2 + 3x - 3 = 0\\a=1\,,\ \ b=3\,,\ \ c=-3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-3)}}{2\cdot1}=\dfrac{-3\pm\sqrt{9+12}}{2}=\dfrac{-3\pm\sqrt{21}}{2}[/tex]
