Answer:
1. i^20 X (2+i^22)
2. i² X (i¹¹-1) X (i²² + i¹¹ + 1) X (i^66 + i³³ + 1)
Step-by-step explanation:
1) 2i^20 + i^42
factor out i^20
i^20 X (2 + i^22)
2) i^101 - i²
i²X(i^99-1)
i²X(i³³-1)X(i^66+i³³+1)
Using a³-b³=(a-b)(a²+ab+b²)
i²X(i¹¹-1)X(i²²+i¹¹+1)X(i^66+i³³+1)
i²X(i¹¹-1)X(i²²+i¹¹+1)X(i^66+i³³+1)
I almost gave up typing. Quite stressful, but its fine
