Answer: the smallest initial velocity that is required to throw the stone is 56 ft/s
Step-by-step explanation:
We know that;
u = initial velocity
v = final velocity = 0
a = acceleration = -g = -32,
s = distance travelled = 49 feet
V² - u² = 2aS
we substitute
0² - u² = 2 × -32 × 49
0 - u² = -3136
u² = 3136
u = √3136
u = 56 ft/s
Therefore the smallest initial velocity that is required to throw the stone is 56 ft/s
