Answer:
Question 2: √x
Question 5: B and D
Step-by-step explanation:
If you move a factor from the denominator to the numberator (or vice versa) its exponent must flip sign.
I.e., [tex]\frac{1}{x^{-1}}[/tex] will become [tex]\frac{x^1}{1}}[/tex] which is x
Multiplying the same number x you must add the exponents. (1/3)+(1/3)+(1/3) is 1, so D is also x¹.
Therefore B and D are equivalent.
