kiaramackey06 kiaramackey06
  • 03-11-2020
  • Chemistry
contestada

Calcuate the number of
grams of solute in 453.9mL
of 0.237 M calcium acetate

Respuesta :

ardni313
ardni313 ardni313
  • 03-11-2020

The number of  grams : 17.082 g

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

453.9 mL  of 0.237 M calcium acetate

  • mol

[tex]\tt mol=M\times V=0.237\times 0.4539=0.108[/tex]

  • mass

MW Ca(C₂H₃OO)₂ : 158,17 g/mol

[tex]\tt mass=mol\times MW\\\\mass=0.108\times 158.17=17.082~g[/tex]

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