Answer:
the end behavior of h(x) matches the end behavior of x
3 zeros, 2 turns
Step-by-step explanation:
The polynomial is of degree 3, so will have a maximum of ...
Because the degree is odd the signs of the end values of h(x) will be different. Because the leading coefficient is positive, the signs of the end values of h(x) will match the sign of x:
- as x → -∞, h(x) → -∞
- as x → ∞, h(x) → ∞
