Answer:
[tex]\bold{\underline{x\in(-\infty\,,\,-4\big>\cup\big<6\,,\,\infty)}}[/tex]
Step-by-step explanation:
[tex]\bold{2|x-1|\geqslant10}\\\\{}\ \div2\qquad\div2\\\\\bold{|x-1|\geqslant5}\\\\\bold {x-1\geqslant5\qquad\quad\vee\qquad x-1\leqslant-5}\\\\\bold {x\geqslant6\qquad\qquad\vee\qquad\ \ x\leqslant-4}\\\\\bold{\underline{x\in(-\infty\,,\,-4\big>\cup\big<6\,,\,\infty)}}[/tex]
