Answer:
[tex]\large \boxed{\sf \bf \ \ \text{No solution in }\mathbb{R} \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
We can say that y = y, right? So it gives.
[tex](x+2)^2+1=x+1\\\\\text{*** We develop the left side. ***}\\\\x^2+2\cdot 2\cdot x + 2^2+1=x+1\\\\\text{*** We subtract x+1. ***}\\\\x^2+4x+5-x-1=0\\\\x^2+3x+4=0[/tex]
[tex]\Delta=b^2-4ac = 3^2-4*4=9-16=-7<0!!!![/tex]
The Delta is negative so there is no solution.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
