Answer:
[see below]
Step-by-step explanation:
I am assuming that you mean: [tex]y-3=4(x-2)[/tex].
The equation is in point slope form...
[tex]y-y_1=m(x-x_1)[/tex]
The point used in the equation is (2, 3). 2 replaces 'x1' and 3 replaces 'y1'.
If you convert the equation in to slope intercept form:
[tex]y-3=4(x-2)\\\\y-3=4x-8\\\\y-3+3=4x-8+3\\\\\boxed{y=4x-5}[/tex]
You get -5 as the y-intercept.
So, the line you draw would pass through points (2,3) and (0,-5).
Hope this helps.
