The height of fall of the stuntman after 2 seconds is 19.6 m.
The vertical height of fall of a projectile is the distance traveled by the projectile.
It can also be described as the path of trajectory of the projectile. The vertical motion of a projectile is affected by force of gravity.
The height of fall of the stuntman after 2 seconds is calculated as follows;
h = ¹/₂gt²
where;
substitute the given parameters and solve for height attained by the stuntman.
h = ¹/₂(9.8)(2²)
h = 19.6 m
Thus, the height of fall of the stuntman after 2 seconds is 19.6 m.
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