jwbri
jwbri jwbri
  • 04-01-2020
  • Mathematics
contestada

Can anyone help me solve this.I need proper equation..Thanks​

Can anyone help me solve thisI need proper equationThanks class=

Respuesta :

jimrgrant1 jimrgrant1
  • 04-01-2020

Answer:

y = 9[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = [tex]\frac{1}{\sqrt{2} }[/tex]

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{9}{y}[/tex]

Multiply both sides by y

y × sin45° = 9, that is

y × [tex]\frac{1}{\sqrt{2} }[/tex] = 9

Multiply both sides by [tex]\sqrt{2}[/tex]

y = 9[tex]\sqrt{2}[/tex]

Answer Link
Stefanisaska
Stefanisaska Stefanisaska
  • 04-01-2020

Answer: ?=9

                √2

Step-by-step explanation:

x=9 =a side of squre

y=diagonal

use equation :

y=a√2

y=9√2

y=12.69

Answer Link

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