Answer:
x=-1 and x=5
Step-by-step explanation:
we have
[tex]x^{2} -4x=5[/tex]
Solve it by completing the square method
We take the coefficient of x that is -4, divide it by 2 and then square it
so
[tex]-\frac{4}{2}=-2[/tex]
square it
[tex](-2)^2 = 4[/tex]
Adds 4 both sides
[tex]x^{2} -4x+4=5+4[/tex]
Combine like terms right side
[tex]x^{2} -4x+4=9[/tex]
Rewrite as perfect squares
[tex](x-2)^{2}=9[/tex]
take square root both sides
[tex]x-2=\pm3[/tex]
[tex]x=2\pm3[/tex]
therefore
[tex]x=2+3=5[/tex]
[tex]x=2-3=-1[/tex]
