Answer:
[tex]\large\boxed{C.\ (1.5,\ -4)}[/tex]
Step-by-step explanation:
The formula of a midpoint of a segment AB with endpoints at A(x₁, y₁) and B(x₂, y₂):
[tex]M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)[/tex]
We have the points P(-6, 3) and Q(9, -11).
Substitute:
[tex]M_{PQ}(x,\ y)\\\\x=\dfrac{-6+9}{2}=\dfrac{3}{2}=1.5\\\\y=\dfrac{3+(-11)}{2}=\dfrac{-8}{2}=-4[/tex]
