Answer:
(2, 8)
Step-by-step explanation:
A hole occurs when the denominator is equal to 0. In this case, the denominator equals zero when x = 2.
Next, we must find the value of y by factoring the numerator and simplifying:[tex]\frac{x^{2} +4x-12}{x-2} = \frac{(x-2)(x+6)}{x-2} = x+6[/tex]
Then plug in 2 for x:
2 + 6 = 8.
Therefore, there is a hole at (2, 8)
