Answer:
A. 3 × 10¹³
Step-by-step explanation:
We have the numbers, 9 × 10⁸ than 3 × 10⁻⁵.
To find the factor by which 9 × 10⁸ is greater by 3 × 10⁻⁵ is given by,
[tex]\frac{9\times 10^{8}}{3\times 10^{-5}}[/tex]
i.e. [tex]\frac{3\times 10^{8+5}}[/tex]
i.e. [tex]\frac{3\times 10^{13}}[/tex]
So, 9 × 10⁸ is 3 × 10¹³ times greater than 3 × 10⁻⁵.
i.e. 3 × 10⁻⁵ × 3 × 10¹³ = 3 × 3 × 10⁻⁵⁺¹³ = 9 × 10⁸.
Hence, option A is correct.
